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[brand]

hi there friends sorry to keep asking for help but i am still learning and i have tryed every way to do this

$sex=mysql_fetch_array(mysql_query("SELECT sex FROM users WHERE sex >'F'"));
if($sex[0]>F){
  <a href=\"../avatars2/avatars.php?sid=$sid\">Female Avatars</a> <br/>Random Female Avatars Coming soon Here<br/>
}

i am after making it so only female members can see the links

i am very great full for all the help every one is giving me

[GumSlone]

$sex=mysql_fetch_array(mysql_query("SELECT sex FROM users WHERE user_id ='".intval($user_id)."'"));
if($sex[0]=='F'){  echo '<a href="http://coding-talk.com/f23/avatars2/avatars.php?sid=$sid">Female Avatars</a> <br/>Random Female Avatars Coming soon Here<br/>';} 

[brand]

$sex=mysql_fetch_array(mysql_query("SELECT sex FROM users WHERE user_id ='".intval($user_id)."'"));if($sex[0]=='F'){  echo '<a href=\"../avatars2/avatars.php?sid=$sid\">Female Avatars</a> <br/>Random Female Avatars Coming soon Here<br/>';} 

thanks gunslone i tryed what ya said and i get this error

Parse error: syntax error, unexpected '}' in /home/**/public_html/mixavatars/main.php on line 29

[metulj]

thanks gunslone i tryed what ya said and i get this error

Parse error: syntax error, unexpected '}' in /home/**/public_html/mixavatars/main.php on line 29

dont you think this error is self explanatory ?
simple delete sign } in line 29 or even in line 28

[brand]

dont you think this error is self explanatory ?
simple delete sign } in line 29 or even in line 28

all sorted now i had to change bits in it to work