any1 have a prate table sql 4 spiderwap script ???pls upload here...tnks...
Ibwf_prate Table Need
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it aint that hard to reverse the tables from code......
try it, you might suprise yaself with how easy it actually is
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with this I have error...Use the search, its laready on here[/b]
Code:CREATE TABLE ibwf_prate ( id int(100) NOT NULL auto_increment, pid int(100) NOT NULL default '0', uid int(100) NOT NULL default '0', prate char(1) NOT NULL, PRIMARY KEY (id)) ENGINE=MyISAM DEFAULT CHARSET=latin1
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this is my error:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/web/www.mysite.net/www/web/gallery.php on line 529
at 529 line I have:
$vb = mysql_fetch_array(mysql_query("SELECT COUNT(*) FROM prate WHERE uid='".$uid."' AND pid='".$gid."'"));
pls any1 can help me???
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you joined here on 24-December 06,still you are **** in simple coding,ppl here are 2much bothered for your stupid posting and want you not to post craps here but you are shameless stupid who always moan here for help,now stop posting ****s here,you make this site filthythis is my error:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/web/www.mysite.net/www/web/gallery.php on line 529
at 529 line I have:
$vb = mysql_fetch_array(mysql_query("SELECT COUNT(*) FROM prate WHERE uid='".$uid."' AND pid='".$gid."'"));
pls any1 can help me???
[/b]
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i think u need to make it ..
try if it worksCode:$vb = mysql_fetch_array(mysql_query("SELECT COUNT(*) FROM ibwf_prate WHERE uid='".$uid."' AND pid='".$gid."'"));<span style="font-size:12pt;line-height:100%"><span style="color:#FF0000">ViSiT Ma SiTe Nd PoSt Ua CoMmEnTs On It In Ma PoSt</span></span>
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