How to code chnage room using drop down menu for lavalair?
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Originally posted by cipap View PostHow to code chnage room using drop down menu for lavalair?PHP Code:<?
<select>
<option>Select Room</option>
<option onpick= "chat.php?sid=ur_s_id&rid=1">Room 1</option>
<option onpick= "chat.php?sid=ur_s_id&rid=2">Room 2</option>
<option onpick= "chat.php?sid=ur_s_id&rid=3">Room 3</option>
<option onpick= "chat.php?sid=ur_s_id&rid=4">Room 4</option>
<option onpick= "chat.php?sid=ur_s_id&rid=5">Room 5</option>
<option onpick= "chat.php?sid=ur_s_id&rid=6">Room 6</option>
</select>
?>
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can i get the code for html??i have try to use this code but fail
$rid = mysql_fetch_array(mysql_query("SELECT id FROM ibwf_rooms WHERE id='".$who."'"));
echo "<form action=\"chat.php?&sid=$sid&rid=$rid\" method=\"post\">";
echo "Change Room: <select name=\"rid\" value=\"$rid[0]\">";
if($rid[0]=="1"){$selected=" selected=\"selected\"";}else{$selected="";}
echo "<option value=\"1\"$selected>room1</option>";
if($rid[0]=="2"){$selected=" selected=\"selected\"";}else{$selected="";}
echo "<option value=\"2\"$selected>room2</option>";
if($rid[0]=="3"){$selected=" selected=\"selected\"";}else{$selected="";}
echo "<option value=\"3\"$selected>room3</option>";
if($rid[0]=="4"){$selected=" selected=\"selected\"";}else{$selected="";}
echo "<option value=\"4\"$selected>room4</option>";
echo "</select><br/>";
echo "<input type=\"Submit\" Name=\"Submit\" Value=\"Change\"></form>
i think the wrong part is at WHERE id='".$who."'"));
anybody can help me?
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Originally posted by cipap View Postcan i get the code for html??i have try to use this code but fail
$rid = mysql_fetch_array(mysql_query("SELECT id FROM ibwf_rooms WHERE id='".$who."'"));
echo "<form action=\"chat.php?&sid=$sid&rid=$rid\" method=\"post\">";
echo "Change Room: <select name=\"rid\" value=\"$rid[0]\">";
if($rid[0]=="1"){$selected=" selected=\"selected\"";}else{$selected="";}
echo "<option value=\"1\"$selected>room1</option>";
if($rid[0]=="2"){$selected=" selected=\"selected\"";}else{$selected="";}
echo "<option value=\"2\"$selected>room2</option>";
if($rid[0]=="3"){$selected=" selected=\"selected\"";}else{$selected="";}
echo "<option value=\"3\"$selected>room3</option>";
if($rid[0]=="4"){$selected=" selected=\"selected\"";}else{$selected="";}
echo "<option value=\"4\"$selected>room4</option>";
echo "</select><br/>";
echo "<input type=\"Submit\" Name=\"Submit\" Value=\"Change\"></form>
i think the wrong part is at WHERE id='".$who."'"));
anybody can help me?
PHP Code:$rooms = mysql_query("SELECT id, name, perms, mage, chposts FROM ibwf_rooms WHERE static='1' AND clubid='0'");
while ($room= mysql_fetch_array($rooms))
{
if(canenter($room[0], $sid))
{
$noi = mysql_fetch_array(mysql_query("SELECT COUNT(*) FROM ibwf_chonline WHERE rid='".$room[0]."'"));
echo "<option value=\"$room[0]\">$room[1]($noi[0])</option>";
//its not the full cod u can use that for ur code:)
}
}
Last edited by i0nutzxp; 30.06.09, 14:48.<?php unlink('World/Europe/Romania.country'); ?>
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how to change this into html??
echo"change room";
$rss = mysql_query("SELECT name, id FROM ibwf_rooms");
echo "<br/><select name=\"chrid\">";
while($rs=mysql_fetch_array($rss))
{
echo "<option value=\"$rs[1]\">$rs[0]</option>";
}
echo "</select><br/>";
echo "<br/><anchor>Go<go href=\"chat.php\" method=\"get\">";
echo "<postfield name=\"rid\" value=\"$(chrid)\"/>";
echo "<postfield name=\"sid\" value=\"$sid\"/>";
echo "</go></anchor>";
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