ip problem

[thunderwap]

hello

why google and my site shows weird ip address of me. i checked few other ip check sites and they showed well in i.e ip2location.com

please see screenshot of google showing my ip

my site also showing same ip as google showing. but in other few sites it shows my real ip address.

what is the wrong with my code in php?

i am using

 $myip = $_SERVER["REMOTE_ADDR"];  

echo "$myip"; 

i also tried explode method with it but though it shows same error

please see screenshot.

[tupac]

I think this is the new version of ip addresses bro nothing to worry about....and to my knowledge the code looks perfectly fine

[wapxtech]

It's your IP, you may be expecting IPv4, but your ISP use's IPv6

[thunderwap]

what do i do to show ip adddress even if my isp uses IPv6?

i want to show both IPv4 and IPv6


will this work if i use

function get_client_ip() {
$ipaddress = '';
if (isset($_SERVER['HTTP_CLIENT_IP']))
$ipaddress = $_SERVER['HTTP_CLIENT_IP'];
else if(isset($_SERVER['HTTP_X_FORWARDED_FOR']))
$ipaddress = $_SERVER['HTTP_X_FORWARDED_FOR'];
else if(isset($_SERVER['HTTP_X_FORWARDED']))
$ipaddress = $_SERVER['HTTP_X_FORWARDED'];
else if(isset($_SERVER['HTTP_FORWARDED_FOR']))
$ipaddress = $_SERVER['HTTP_FORWARDED_FOR'];
else if(isset($_SERVER['HTTP_FORWARDED']))
$ipaddress = $_SERVER['HTTP_FORWARDED'];
else if(isset($_SERVER['REMOTE_ADDR']))
$ipaddress = $_SERVER['REMOTE_ADDR'];
else
$ipaddress = 'UNKNOWN';
return $ipaddress;
} 

[something else]

function getIp()
{
    $ip = $_SERVER['REMOTE_ADDR'];
    if(substr_count($ip,':')>2)
    {
        $ip = hexdec(substr($ip, 0, 2)). "." . hexdec(substr($ip, 2, 2)). "." . hexdec(substr($ip, 5, 2)). "." . hexdec(substr($ip, 7, 2));
    }
    return $ip;
}