PHP Code:
else if
$show = $mob1;
else
$show = $mob2;
return $show;
Parse error: syntax error, unexpected T_VARIABLE, expecting '(' in /home/abcd/public_html/index.php on line 25
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its giving me error
Parse error: syntax error, unexpected T_VARIABLE, expecting '(' in /home/abcd/public_html/index.php on line 25 -
What is the condition you try by putting else if ?Originally posted by slowy View Post
I dont know....but this will work
PHP Code:else if(your condition){
$show = $mob1;
}else{
$show = $mob2;
}
return $show;
I'm Proud to be a Sri Lankan! -
Try like this
PHP Code:elseif($condition) {
$show = $mob1;
}
else {
$show = $mob2;
}
return $show;
Last edited by ReazulIqbal; 04.06.11, 07:55.Comment
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Originally posted by slowy View Post
your condition is missing from the else if
try this :
PHP Code:else if (<condition>)
$show = $mob1;
else
$show = $mob2;
return $show;
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