options form

[crazybrumi]

ended up scraping the idea of directory index and just put everything into a sql

[arnage]

i have narrowed the problem down to this it wont work if i do it like this

$main.="<option value=\"$file_name[0]\">$file_name[0]</option>"; 

but will work if i have it like this ??

echo"<option value=\"$file_name[0]\">$file_name[0]</option>"; 

but as im using

$main.="sample"; 

it will appear at the top of the page

this is from the directory index code

From where are you getting $file_name?
This behavior usualy happens when some function is used in which the data is not executed, should be like this for example:
... $var ... code;
return $var;

[kevk3v]

how about

$main.='<option value="'.htmlspecialchars($file_name[0], ENT_QUOTES).'">'.htmlspecialchars($file_name[0], ENT_QUOTES).'</option>'; 

then use

htmlspecialchars_decode(); 

[crazybrumi]

i have narrowed the problem down to this it wont work if i do it like this

$main.="<option value=\"$file_name[0]\">$file_name[0]</option>"; 

but will work if i have it like this ??

echo"<option value=\"$file_name[0]\">$file_name[0]</option>"; 

but as im using

$main.="sample"; 

it will appear at the top of the page

this is from the directory index code

[just_m3.]

Yep, thanks. But on second look it needs some loop also, depending what is getting with capture function, otherwise it ain't gonna work.

he just posted some lines of the code , i think he is just protecting the value of the script =).

[arnage]

Yep, thanks. But on second look it needs some loop also, depending what is getting with capture function, otherwise it ain't gonna work.

[just_m3.]

$main.="HAT: <select name=\"hat\">";
if (!empty($_GET["hat"])){
$main.="<option value=\"$hat\">$hat</option>";
}else {
$main.="<option value=\"\">select</option>";
$main.="".capture("hat)."";
}
$main.="</select><br/>"; 

cant seem to get list of images in directory to show as an option value in a form
capture is the the function that searches directory.

What are you doing with $main ? post full code i can't know what you are trying to do with only "that" .

Added after 6 minutes:

Try to add capture() in option value tag?
Im by phone now and i can't write some chars.

Like this ?:

$main.="HAT: <select name=\"hat\">"; 
if (!empty($_GET["hat"])){ 
$main.="<option value=\"$hat\">$hat</option>"; 
}else { 
$main.="<option value=\"\">select</option>"; 
//here list it 
$main.="<option value=\"".capture("hat")."\">".capture("hat")."</option>"; 
} 
$main.="</select><br/>"; 

[arnage]

Try to add capture() in option value tag?
Im by phone now and i can't write some chars.

[crazybrumi]

$main.="HAT: <select name=\"hat\">";
if (!empty($_GET["hat"])){
$main.="<option value=\"$hat\">$hat</option>";
}else {
$main.="<option value=\"\">select</option>";
$main.="".capture("hat)."";
}
$main.="</select><br/>"; 

cant seem to get list of images in directory to show as an option value in a form
capture is the the function that searches directory.